Converters
Converter for temperature
Change temperature between Celsius, Fahrenheit and Kelvin, with all di scales side by side.
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Your numbers
Result dey update as you type; no Calculate button dey. All calculation dey run inside your browser.
Temperature after conversion
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All scales for this temperature
| Scale | Value wey e get |
|---|
All three rows na di same temperature dem describe. Di page no dey accept or convert values below absolute zero.
Formula
Change di original temperature to Celsius, then use di equation for di scale wey you want.
| Conversion | Formula |
|---|---|
| °F to °C | °C = (°F − 32) × 5/9 |
| °C to °F | °F = °C × 9/5 + 32 |
| °C to K | K = °C + 273.15 |
| K to °C | °C = K − 273.15 |
Absolute zero na 0 K = −273.15 °C = −459.67 °F. Any input wey mean negative Kelvin no possible physically, so di page no dey accept am.
Example wey show the calculation
25 °C × 9/5 + 32 = 77 °F, and 25 + 273.15 = 298.15 K. Di scales meet at −40: −40 × 9/5 + 32 = −40 °F.
Where e fit work and limits
Temperature difference no be di same as absolute temperature: rise of 1 °C na di same as rise of 1 K, but rise of 1.8 °F. Dis page dey convert absolute temperatures, no be differences. Dem round di displayed values to 6 decimal places. Rounding fit change di last decimals wey you see, as di source tool note.
Questions wey people dey ask often
Wetin be absolute zero?
0 K = −273.15 °C = −459.67 °F — na di coldest temperature wey possible. Dis page no dey accept anything colder.
Why °C and °F dey meet at −40?
If you solve C = C × 9/5 + 32, you go get C = −40, di only temperature wey get di same number for both scales.
0 °C na the same as 32 °F?
Yes: water dey freeze at 0 °C = 32 °F = 273.15 K under standard atmospheric pressure.
How I fit convert temperature difference?
For temperature difference, remove di +32/+273.15 offsets: 10 °C warming = 18 °F warming = 10 K warming.
Why na 273.15 and no be 273?
273.15 na di exact offset between Celsius and Kelvin scales, as di definition of kelvin set am.
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Results na estimates; dem no replace advice from qualified professional.