Time for Insulation Savings to Cover Cost
Estimate conduction savings and simple time to recover insulation installation cost.
Your numbers
Energy money wey you save for one year
Steady degree-day estimate; air leakage, cooling changes, rebound, finance and energy-price changes no join.
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Formula
Use E = A(Uₒ−Uₙ)D×24/(1000η). A na area for m²; Uₒ and Uₙ na old and new transmittance for W/m²·K; D na annual heating degree days for K·day; η na system efficiency. E na annual energy saving for kWh.
Estimate conduction savings and simple time to recover insulation installation cost.
Example wey show the calculation
- Area of building envelope (m²)
- 100
- Heat-transmittance U value before work (W/m²·K)
- 1
- Heat-transmittance U value after work (W/m²·K)
- 0.5
- Heating degree days for one year (K·day)
- 2000
- Efficiency of the heating system
- 1
- Price of energy for each kWh
- 0.2
- Cost to install am
- 1000
- Energy money wey you save for one year
- 2,400 kWh
- Yearly bill saving
- 480
- Simple time to recover cost
- 2.08333 years
Where e fit work and limits
Steady degree-day estimate; air leakage, cooling changes, rebound, finance and energy-price changes no join.
We check inputs for missing values and allowed ranges. Result wey pass the finite numeric range no go show. Rounding affect wetin display, while calculation use the model numeric precision.
Check your units and assumptions before you rely on result. Changing label no convert currency or physical unit.
Version of di formula: 966099260e37 · Example don get check: